Q. No.(Given density of water = \(10^3 ~\text{kgm}^{-3},~ g=10 ~\text{ms}^{-2} \) and \(1~\text{atm} = 10^5~\text{Pa}\))
| 1. | \(1~\text{atm}\) | 2. | \(2~\text{atm}\) |
| 3. | \(3~\text{atm}\) | 4. | \(4~\text{atm}\) |
| 1. | The coefficient of viscosity is a scalar quantity. |
| 2. | Surface tension is a scalar quantity. |
| 3. | Pressure is a vector quantity. |
| 4. | Relative density is a scalar quantity. |
| 1. | pressure on the base area of vessels \(A\) and \(B\) is the same. |
| 2. | pressure on the base area of vessels \(A\) and \(B\) is not the same. |
| 3. | both vessels \(A\) and \(B\) weigh the same. |
| 4. | vessel \(B\) weighs twice that of \(A\). |
A barometer is constructed using a liquid (density = \(760~\text{kg/m}^3\)). What would be the height of the liquid column, when a mercury barometer reads \(76~\text{cm}?\)
(the density of mercury = \(13600~\text{kg/m}^3\))
| 1. | \(1.36~\text m\) | 2. | \(13.6~\text m\) |
| 3. | \(136~\text m\) | 4. | \(0.76~\text m\) |
In a U-tube, as shown in the figure, the water and oil are in the left side and right side of the tube respectively. The height of the water and oil columns are \(15~\text{cm}\) and \(20~\text{cm}\) respectively. The density of the oil is:
\(\left[\text{take}~\rho_{\text{water}}= 1000~\text{kg/m}^{3}\right]\)
| 1. | \(1200~\text{kg/m}^{3}\) | 2. | \(750~\text{kg/m}^{3}\) |
| 3. | \(1000~\text{kg/m}^{3}\) | 4. | \(1333~\text{kg/m}^{3}\) |
A \(U\text-\)tube with both ends open to the atmosphere is partially filled with water. Oil, which is immiscible with water, is poured into one side until it stands at a level of \(10~\text{mm}\) above the water level on the other side. Meanwhile, the water rises by \(65~\text{mm}\) from its original level (see diagram). The density of the oil is:
| 1. | \(425~\text{kg m}^{-3}\) | 2. | \(800~\text{kg m}^{-3}\) |
| 3. | \(928~\text{kg m}^{-3}\) | 4. | \(650~\text{kg m}^{-3}\) |
The heart of a man pumps \(5~\text{L}\) of blood through the arteries per minute at a pressure of \(150~\text{mm}\) of mercury. If the density of mercury is \(13.6\times10^{3}~\text{kg/m}^{3}\) \(g = 10~\text{m/s}^2,\) then the power of the heart in watts is:
| 1. | \(1.70\) | 2. | \(2.35\) |
| 3. | \(3.0\) | 4. | \(1.50\) |
The approximate depth of an ocean is \(2700~\text{m}\). The compressibility of water is \(45.4\times10^{-11}~\text{Pa}^{-1}\) and the density of water is \(10^{3}~\text{kg/m}^3\). What fractional compression of water will be obtained at the bottom of the ocean?
| 1. | \(0.8\times 10^{-2}\) | 2. | \(1.0\times 10^{-2}\) |
| 3. | \(1.2\times 10^{-2}\) | 4. | \(1.4\times 10^{-2}\) |
| 1. | \([2+(n+1)r ]\rho\) | 2. | \([2+(n-1)r] \rho\) |
| 3. | \([1+(n-1)r] \rho\) | 4. | \([1+(n+1)r ]\rho\) |
The cylindrical tube of a spray pump has a radius \(R,\) one end of which has \(n\) fine holes, each of radius \(r.\) If the speed of the liquid in the tube is \(v,\) the speed of the ejection of the liquid through the holes is:
| 1. | \(\dfrac{vR^{2}}{n^{2}r^{2}}\) | 2. | \(\dfrac{vR^{2}}{nr^{2}}\) |
| 3. | \(\dfrac{vR^{2}}{n^{3}r^{2}}\) | 4. | \(\dfrac{v^{2}R}{nr}\) |
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