| 1. | \(13:1\) and \(14:1\) | 2. | \(14:1\) and \(1:1\) |
| 3. | \(1:1\) and \(14:1\) | 4. | \(1:1\) and \(13:1\) |
| 1. | \(4.5\times10^{13}~\text J\) | 2. | \(1.5\times10^{13}~\text J\) |
| 3. | \(0.5\times10^{13}~\text J\) | 4. | \(4.5\times10^{16}~\text J\) |
| A. | slow neutrons can cause fission in \(\mathrm U_{92}^{235}\) than fast neutrons. |
| B. | \(\text{α-rays}\) are helium nuclei. |
| C. | \(\text{β-rays}\) are fast-moving electrons or positrons. |
| D. | \(\gamma\text-\text{rays}\) are electromagnetic radiations of wavelengths larger than \(X\text-\)rays. |
| 1. | A, B, and C only | 2. | A, B, and D only |
| 3. | A and B only | 4. | C and D only |
A nucleus with mass number \(240\) breaks into fragments each of mass number \(120.\) The binding energy per nucleon of unfragmented nuclei is \(7.6~\text{MeV}\) while that of fragments is \(8.5~\text{MeV}.\) The total gain in the binding energy in the process is:
| 1. | \(804~\text{MeV}\) | 2. | \(216~\text{MeV}\) |
| 3. | \(0.9~\text{MeV}\) | 4. | \(9.4~\text{MeV}\) |
If the radius of \(_{13}^{27}\mathrm{Al}\) nucleus is taken to be \({R}_{\mathrm{Al}},\) then the radius of \(_{53}^{125}\mathrm{Te}\) nucleus is near:
| 1. | \(\left(\frac{53}{13}\right) ^{\frac{1}{3}}~{R_{Al}}\) | 2. | \(\frac{5}{3}~{R_{Al}}\) |
| 3. | \(\frac{3}{5}~{R_{Al}}\) | 4. | \(\left(\frac{13}{53}\right)~{R_{Al}}\) |
The Binding energy per nucleon of \(^{7}_{3}\mathrm{Li}\) and \(^{4}_{2}\mathrm{He}\) nucleon are \(5.60~\text{MeV}\) and \(7.06~\text{MeV}\), respectively. In the nuclear reaction \(^{7}_{3}\mathrm{Li} + ^{1}_{1}\mathrm{H} \rightarrow ^{4}_{2}\mathrm{He} + ^{4}_{2}\mathrm{He} +Q\), the value of energy \(Q\) released is:
| 1. | \(19.6~\text{MeV}\) | 2. | \(-2.4~\text{MeV}\) |
| 3. | \(8.4~\text{MeV}\) | 4. | \(17.3~\text{MeV}\) |
| 1. | decrease continuously with mass number. |
| 2. | first decreases and then increases with an increase in mass number. |
| 3. | first increases and then decreases with an increase in mass number. |
| 4. | increases continuously with mass number. |