Q. No.In hydrogen spectrum, the shortest wavelength in the Balmer series is \(\lambda\). The shortest wavelength in the Bracket series is:
1. \(16\lambda\)
2. \(2\lambda\)
3. \(4\lambda\)
4. \(9\lambda\)
1. \(16\lambda\)
2. \(2\lambda\)
3. \(4\lambda\)
4. \(9\lambda\)
Subtopic: Spectral Series |
66%
Level 2: 60%+
NEET - 2023
Hints
Electron in hydrogen atom first jumps from the third excited state to the second excited state and then from the second excited to the first excited state. The ratio of the wavelengths \(\lambda_1:\lambda_2\) emitted in the two cases is:
1. \(\dfrac{7}{5}\)
2. \(\dfrac{20}{7}\)
3. \(\dfrac{27}{5}\)
4. \(\dfrac{27}{20}\)
1. \(\dfrac{7}{5}\)
2. \(\dfrac{20}{7}\)
3. \(\dfrac{27}{5}\)
4. \(\dfrac{27}{20}\)
Subtopic: Spectral Series |
73%
Level 2: 60%+
AIPMT - 2012
Hints
Links
The spectral series which corresponds to the electronic transition from the levels \({n}_{2}=5,6,\ldots \) to the level \({n}_{1}=4\mathrm~\) is:
| 1. | Pfund series | 2. | Brackett series |
| 3. | Lyman series | 4. | Balmer series |
Subtopic: Spectral Series |
81%
Level 1: 80%+
NEET - 2024
Hints
Some energy levels of a molecule are shown in the figure with their wavelengths of transitions.
Then:
1. \(\lambda_{3}>\lambda_{2},\lambda_{1}=2\lambda_{2}\)
2. \(\lambda_{3}>\lambda_{2},\lambda_{1}=4\lambda_{2}\)
3. \(\lambda_{1}>\lambda_{2},\lambda_{2}=2\lambda_{3}\)
4. \(\lambda_{2}>\lambda_{1},\lambda_{2}=2\lambda_{3}\)
Then:
1. \(\lambda_{3}>\lambda_{2},\lambda_{1}=2\lambda_{2}\)
2. \(\lambda_{3}>\lambda_{2},\lambda_{1}=4\lambda_{2}\)
3. \(\lambda_{1}>\lambda_{2},\lambda_{2}=2\lambda_{3}\)
4. \(\lambda_{2}>\lambda_{1},\lambda_{2}=2\lambda_{3}\)
Subtopic: Spectral Series |
55%
Level 3: 35%-60%
NEET - 2024
Hints
Match List-I (Spectral Series) with List-II (corresponding wave number expressions).
Choose the correct answer from the options given below:
| List-I (Series) |
List-II (Wave number in \(\text{cm}^{–1}\)) |
||
| A. | Balmer series | I. | \( R\left(\dfrac{1}{1^2}-\dfrac{1}{n^2}\right) \) |
| B. | Lyman series | II. | \( R\left(\dfrac{1}{4^2}-\dfrac{1}{n^2}\right) \) |
| C. | Brackett series | III. | \( R\left(\dfrac{1}{5^2}-\dfrac{1}{n^2}\right) \) |
| D. | Pfund series | IV. | \( R\left(\dfrac{1}{2^2}-\dfrac{1}{n^2}\right)\) |
Choose the correct answer from the options given below:
| 1. | A-I, B-IV, C-III, D-II |
| 2. | A-II, B-III, C-IV, D-I |
| 3. | A-IV, B-I, C-II, D-III |
| 4. | A-III, B-II, C-I, D-IV |
Subtopic: Spectral Series |
86%
Level 1: 80%+
NEET - 2024
Hints
Match List-I with List-II.
Choose the correct answer from the options given below:
| List-I (Spectral Lines of Hydrogen for transitions from) |
List-II (Wavelength (nm)) |
||
| \(\mathrm{A.}\) | \(n_2=3\) to \(n_1=2\) | \(\mathrm{I.}\) | \(410.2\) |
| \(\mathrm{B.}\) | \(n_2=4\) to \(n_1=2\) | \(\mathrm{II.}\) | \(434.1\) |
| \(\mathrm{C.}\) | \(n_2=5\) to \(n_1=2\) | \(\mathrm{III.}\) | \(656.3\) |
| \(\mathrm{D.}\) | \(n_2=6\) to \(n_1=2\) | \(\mathrm{IV.}\) | \(486.1\) |
Choose the correct answer from the options given below:
| 1. | \(\mathrm{A - III, B - IV, C - II, D - I}\) |
| 2. | \(\mathrm{A - IV, B - III, C - I, D - II}\) |
| 3. | \(\mathrm{A - I, B - II, C - III, D - IV}\) |
| 4. | \(\mathrm{A - II, B - I, C - IV, D - III}\) |
Subtopic: Spectral Series |
63%
Level 2: 60%+
NEET - 2024
Hints
Given below are two statements:
In the light of the above statements, choose the most appropriate answer from the options given below:
| Statement I: | Atoms are electrically neutral as they contain equal number of positive and negative charges. |
| Statement II: | Atoms of each element are stable and emit their characteristic spectrum. |
| 1. | Both Statement I and Statement II are incorrect. |
| 2. | Statement I is correct but Statement II is incorrect. |
| 3. | Statement I is incorrect but Statement II is correct. |
| 4. | Both Statement I and Statement II are correct. |
Subtopic: Spectral Series |
Level 3: 35%-60%
NEET - 2024
Hints
The wavelength of the Lyman series of hydrogen atom appears in:
| 1. | visible region |
| 2. | far infrared region |
| 3. | ultraviolet region |
| 4. | infrared region |
Subtopic: Spectral Series |
82%
Level 1: 80%+
NEET - 2023
Hints
The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is:
1. \(1\)
2. \(4\)
3. \(0.5\)
4. \(2\)
Subtopic: Spectral Series |
79%
Level 2: 60%+
NEET - 2017
Hints
Links
Given that the value of the Rydberg constant is \(10^{7}~\text{m}^{-1},\) what will be the wave number of the last line of the Balmer series in the hydrogen spectrum?
1. \(0.5 \times 10^{7}~\text{m}^{-1}\)
2. \(0.25 \times 10^{7} ~\text{m}^{-1}\)
3. \(2.5 \times 10^{7}~\text{m}^{-1}\)
4. \(0.025 \times 10^{4} ~\text{m}^{-1}\)
1. \(0.5 \times 10^{7}~\text{m}^{-1}\)
2. \(0.25 \times 10^{7} ~\text{m}^{-1}\)
3. \(2.5 \times 10^{7}~\text{m}^{-1}\)
4. \(0.025 \times 10^{4} ~\text{m}^{-1}\)
Subtopic: Spectral Series |
88%
Level 1: 80%+
NEET - 2016
Hints
Links
© 2026 GoodEd Technologies Pvt. Ltd.