| Statement I: | Aniline does not undergo Friedel-Crafts alkylation reaction. |
| Statement II: | Aniline cannot be prepared through Gabriel synthesis. |
| 1. | Both Statement I and Statement II are incorrect. |
| 2. | Statement I is correct and Statement II is incorrect. |
| 3. | Statement I is incorrect and Statement II is correct. |
| 4. | Both Statement I and Statement II are correct. |
| 1. | Butylamine | 2. | Butanamide |
| 3. | \(\alpha-\) Bromobutanoic acid | 4. | Propylamine |
| 1. | 2. | ||
| 3. | 4. |
| 1. | |
| 2. | ![]() |
| 3. | ![]() |
| 4. | ![]() |
| Column-I (Reaction) |
Column-II (Product formed) |
||
| (a) | Gabriel synthesis | (i) | Benzaldehyde |
| (b) | Kolbe synthesis | (ii) | Ethers |
| (c) | Williamson synthesis | (iii) | Primary amines |
| (d) | Etard reaction | (iv) | Salicylic acid |
| (a) | (b) | (c) | (d) | |
| 1. | (iii) | (i) | (ii) | (iv) |
| 2. | (ii) | (iii) | (i) | (iv) |
| 3. | (iv) | (iii) | (i) | (ii) |
| 4. | (iii) | (iv) | (ii) | (i) |
Match list-I with list-II:
| List-I (Amines) | List-II (pKb values) | ||
| (a) | N-Methylmethanamine | (i) | 9.30 |
| (b) | Ammonia | (ii) | 9.38 |
| (c) | N-Methylaniline | (iii) | 4.75 |
| (d) | Benzenamine | (iv) | 3.27 |
| (a) | (b) | (c) | (d) | |
| 1. | (iv) | (ii) | (i) | (iii) |
| 2. | (iv) | (iii) | (i) | (ii) |
| 3. | (iii) | (iv) | (i) | (ii) |
| 4. | (i) | (iv) | (iii) | (ii) |
The major product (P) formed in the following reaction sequence is :
| 1. | 2. | ||
| 3. | 4. |
| 1. | Ethylamine | 2. | Methylamine |
| 3. | Propylamine | 4. | Aniline |
The nitration of aniline in a strong acidic medium results in the formation of m-nitroaniline because:
| 1. | In spite of substituents, the nitro group always goes to only the m-position. |
| 2. | In electrophilic substitution reactions, the amino group is meta-directive. |
| 3. | In the absence of substituents, the nitro group always goes to only m-position. |
| 4. | In an acidic (strong) medium, aniline is present as an anilinium ion. |